document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=801327>Question 801327</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One interger is 5 less than another. The sum of their squares is 97. Find the intergers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806082 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = y - 5<BR>\n" );
document.write( "x^2 + y^2 = 97\r<BR>\n" );
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document.write( "Substitute x = y - 5 into the second equation.\r<BR>\n" );
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document.write( "(y - 5)^2 + y^2 = 97<BR>\n" );
document.write( "y^2 - 10y + 25 + y^2 = 97<BR>\n" );
document.write( "2y^2 - 10y - 72 = 0<BR>\n" );
document.write( "y^2 - 5y - 36 = 0<BR>\n" );
document.write( "(y - 9)(y + 4) = 0<BR>\n" );
document.write( "y = 9, y = -4\r<BR>\n" );
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document.write( "The integers are (x, y) = (4, 9) and (-9, -4) </SPAN>\n" );
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