document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=806963>Question 806963</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The numerator of a fraction is 6 less than the denominator. If both of these are increased by 4, the resulting fraction will be 5/7. What is the original fraction </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806069 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806069\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x/y\r<BR>\n" );
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document.write( "x = y - 6<BR>\n" );
document.write( "(x + 4)/(y + 4) = 5/7\r<BR>\n" );
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document.write( "Substitute into the second equation.\r<BR>\n" );
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document.write( "(y - 2)/(y + 4) = 5/7<BR>\n" );
document.write( "7(y-2) = 5(y+4)<BR>\n" );
document.write( "7y - 14 = 5y + 20<BR>\n" );
document.write( "2y = 34<BR>\n" );
document.write( "y = 17\r<BR>\n" );
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document.write( "The original fraction is x/y = 11/17. </SPAN>\n" );
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