document.write( "Question 803572: How do I find two consecutive intergers such that twice the smaller is 10 more than 8 times the larger \n" ); document.write( "
Algebra.Com's Answer #806067 by CubeyThePenguin(3113)![]() ![]() You can put this solution on YOUR website! consecutive integers: x, (x+1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x = 8(x+1) + 10 \n" ); document.write( "2x = 8x + 18 \n" ); document.write( "-6x = 18 \n" ); document.write( "x = -3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The integers are -3 and -2. \n" ); document.write( " |