document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=808927>Question 808927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 144. The second number is 6 more than the first . The third number is 4 times the second. What are the numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806050 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + y + z = 144<BR>\n" );
document.write( "y = x + 6<BR>\n" );
document.write( "z = 4y = 4(x + 6)\r<BR>\n" );
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document.write( "Write everything in terms of x.\r<BR>\n" );
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document.write( "x + y + z = 144<BR>\n" );
document.write( "x + (x + 6) + 4(x + 6) = 144<BR>\n" );
document.write( "6x + 30 = 144<BR>\n" );
document.write( "6x = 114<BR>\n" );
document.write( "x = 19\r<BR>\n" );
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document.write( "solution: (x, y, z) = (19, 25, 100) </SPAN>\n" );
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