document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=811662>Question 811662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two numbers such that the sum of the first and three times the second is 5 and the sum of second and two times the first is 8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806022 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806022\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a repeat question.\r<BR>\n" );
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document.write( "x + 3y = 5<BR>\n" );
document.write( "2x + y = 8\r<BR>\n" );
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document.write( "Multiply the second equation by -3 and add:\r<BR>\n" );
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document.write( "x + 3y = 5<BR>\n" );
document.write( "-6x - 3y = -24<BR>\n" );
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document.write( "-5x = -19 ------> x = 19/5\r<BR>\n" );
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document.write( "y = (5 - 19/5)/3 = 2/5\r<BR>\n" );
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document.write( "(x, y) = (19/5, 2/5) </SPAN>\n" );
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