document.write( "Question 823138: Find three consecutive positive integers such that the product of the first two is 22 less than 11 times the third. \n" ); document.write( "
Algebra.Com's Answer #805983 by CubeyThePenguin(3113) You can put this solution on YOUR website! consecutive positive integers: (x-1), x, (x+1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-1)(x) = 11(x+1) - 22 \n" ); document.write( "x^2 - x = 11x - 11 \n" ); document.write( "x^2 - 12x + 11 = 0 \n" ); document.write( "(x - 11)(x - 1) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The integers could be {0, 1, 2} or {10, 11, 12}. \n" ); document.write( " |