document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=828982>Question 828982</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3 consecutive odd integers such that two times the sum of all three is nine less than the product of the first and second integer  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805971 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805971\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> consecutive odd integers: (x-2), x, (x+2)\r<BR>\n" );
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document.write( "2((x-2) + x + (x+2)) = (x-2)(x) - 9<BR>\n" );
document.write( "2(3x) = x^2 - 2x - 9<BR>\n" );
document.write( "6x = x^2 - 2x - 9<BR>\n" );
document.write( "0 = x^2 - 8x - 9<BR>\n" );
document.write( "0 = (x - 9)(x + 1)<BR>\n" );
document.write( "x = 9 or x = -1\r<BR>\n" );
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document.write( "The integers could be {7, 9, 11} or {-3, -1, 1}. </SPAN>\n" );
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