document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=829124>Question 829124</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find 3 consective odd integers such that 8 more than twice the first integer is equal to 19 less than three times the third integer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805969 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805969\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> consecutive odd integers: (x-2), x, (x+2)\r<BR>\n" );
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document.write( "8 + 2(x-2) = 3(x+2) - 19<BR>\n" );
document.write( "2x + 4 = 3x - 13<BR>\n" );
document.write( "17 = x\r<BR>\n" );
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document.write( "The integers are 15, 17, and 19. </SPAN>\n" );
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