document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=835665>Question 835665</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A fishing boat can travel 320 miles in eight hours with the current. Against the current it takes 16 hours to travel the same distance. Find the rate of the fishing boat and the rate of the current </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805957 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> boat speed = x<BR>\n" );
document.write( "current speed = y\r<BR>\n" );
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document.write( "with current: x + y = 320/8 = 40<BR>\n" );
document.write( "against current: x - y = 320/16 = 20\r<BR>\n" );
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document.write( "Add: 2x = 60 ---> x = 30\r<BR>\n" );
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document.write( "The boat travels at 30 mph and the current travels at 10 mph. </SPAN>\n" );
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