document.write( "Question 836986: The perimeter of a rectangle is 46 units. The difference between the length and the width of the rectangle is 13 units. What is the area of the rectangle?
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Algebra.Com's Answer #805953 by CubeyThePenguin(3113) You can put this solution on YOUR website! length = x, width = y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + y = 23 \n" ); document.write( "x - y = 13\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add both equations to get 2x = 36 ---> x = 18. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "18 + y = 23 \n" ); document.write( "y = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "area = xy = (18)(5) = 90 unit^2 \n" ); document.write( " |