document.write( "Question 110626: Solve the proportion.\r
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document.write( "k/28=8/63 \n" );
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Algebra.Com's Answer #80595 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Given the proportion: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "You can start the solution to proportion problems by using a process called \"cross multiplying.\" \n" ); document.write( ". \n" ); document.write( "In this process you multiply the numerator of one side times the denominator of the other \n" ); document.write( "side, then write the equal sign, and follow that by multiplying the numerator of the other \n" ); document.write( "side by the denominator of the first side. A little difficult to describe, but actually \n" ); document.write( "pretty easy to do once you get the hang of it. \n" ); document.write( ". \n" ); document.write( "In this problem we can begin by multiplying the k (a numerator) times the 63 (the denominator \n" ); document.write( "from the other side), then write the equal sign, and on the other side of the equal sign \n" ); document.write( "multiply the 8 (a numerator) times the 28 (denominator from the opposite side). \n" ); document.write( ". \n" ); document.write( "When you do that you have: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now you can solve for k by dividing both sides by 63 (the multiplier of k) to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Notice that 63 factors into 9 times 7. Therefore, you can replace the 63 with 9*7 and the \n" ); document.write( "problem then becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "And the 28 in the numerator factors into 7 times 4. So replace the 28 with 7*4 and the \n" ); document.write( "problem is then: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "You can then cancel the 7 in the numerator with the 7 in the denominator and you have: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Nothing else will cancel nicely, so multiply out the numerator and divide that product \n" ); document.write( "by the denominator to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Hope this helps you. The cross process of cross multiplying is a convenient way to remember \n" ); document.write( "what to do to convert proportions to an ordinary algebraic equation. You might want to \n" ); document.write( "remember it. \n" ); document.write( ". \n" ); document.write( " |