document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=838739>Question 838739</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4 times the third, of three consecutive integers is 51 less than 3 times the sum of the first and second integers.<BR>\n" );
document.write( "Find the third integer? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805947 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805947\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> consecutive integers: (x-1), x, (x+1)\r<BR>\n" );
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document.write( "4(x+1) = 3((x-1) + x) - 51<BR>\n" );
document.write( "4x + 4 = 3(2x - 1) - 51<BR>\n" );
document.write( "4x + 4 = 6x - 54<BR>\n" );
document.write( "58 = 2x<BR>\n" );
document.write( "x = 29\r<BR>\n" );
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document.write( "third integer = x + 1 = 30 </SPAN>\n" );
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