document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=839073>Question 839073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.Write the number in standard notation.\r<BR>\n" );
document.write( "\n" );
document.write( "9.07*10^-2\r<BR>\n" );
document.write( "\n" );
document.write( "2.Suppose a spherical asteroid has a diameter of approximately 3.0*10^3 m.<BR>\n" );
document.write( "a. Find the radius using scientific notation.<BR>\n" );
document.write( "b. Use the formula 4/3to find the approximate volume of the asteroid.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805941 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. 9.07 * 10^(-2) = 0.0907\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2. radius = 1.5 * 10^(3) m\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "volume = (4/3) * pi * (r^3) = (4/3) * pi * (1.5 * 10^(3) m)^3<BR>\n" );
document.write( "= 1.413 * 10^(10) m^3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );