document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=856832>Question 856832</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 3 more than 2 times another. Their product is 27. Find the numbers.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805929 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = 2y + 3<BR>\n" );
document.write( "xy = 27\r<BR>\n" );
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document.write( "Substitute x = 2y + 3 into the second equation.\r<BR>\n" );
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document.write( "(2y + 3)(y) = 27<BR>\n" );
document.write( "2y^2 + 3y - 27 = 0<BR>\n" );
document.write( "(2y + 9)(y - 3) = 0<BR>\n" );
document.write( "y = -9/2 or y = 3\r<BR>\n" );
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document.write( "Solutions: (x, y) = (-6, -9/2) or (9, 3) </SPAN>\n" );
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