document.write( "Question 847376: Find 3 consecutive integers such that the product of 5 and the sum of the first two was 7 greater than the opposite of the third \n" ); document.write( "
Algebra.Com's Answer #805917 by CubeyThePenguin(3113)![]() ![]() You can put this solution on YOUR website! consecutive integers: (x-1), x, (x+1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5((x-1) + x) = -(x+1) + 7 \n" ); document.write( "5(2x - 1) = -x - 1 + 7 \n" ); document.write( "10x - 5 = -x + 6 \n" ); document.write( "11x = 11 \n" ); document.write( "x = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The integers are 0, 1, and 2. \n" ); document.write( " |