document.write( "Question 847820: The sum of three integers is 345. the first and second integer exceeds the third by 77. The third integer is 38 less than the first. find the three integers \n" ); document.write( "
Algebra.Com's Answer #805916 by CubeyThePenguin(3113) You can put this solution on YOUR website! x + y + z = 345 \n" ); document.write( "x + y = z + 77 \n" ); document.write( "z = x - 38\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute the second equation into the first.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x + y) + z = 345 \n" ); document.write( "z + 77 + z = 345 \n" ); document.write( "2z = 268 \n" ); document.write( "z = 134\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "134 = x - 38 ----> x = 172\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "172 + y + 134 = 345 \n" ); document.write( "y = 39\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "integers: (x, y, z) = (172, 39, 134) \n" ); document.write( " |