document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=851190>Question 851190</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given three consecutive integers with a sum of four times the second number, write an algebraic equation for this situation.\r<BR>\n" );
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document.write( "A) n+n+1+n+2=(n+1)<BR>\n" );
document.write( "B) n+n+1+n+2=4n<BR>\n" );
document.write( "C) 3n+3=4n+4<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805905 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805905\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> consecutive integers: n, (n+1), (n+2)\r<BR>\n" );
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document.write( "n + (n+1) + (n+2) = 4(n+1)<BR>\n" );
document.write( "3n + 3 = 4n + 4\r<BR>\n" );
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document.write( "C) is correct. </SPAN>\n" );
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