document.write( "Question 854421: Find the dimensions of the rectangle whose width is 8cm less than its length and whose area is 20 cm^2. \n" ); document.write( "
Algebra.Com's Answer #805894 by CubeyThePenguin(3113) You can put this solution on YOUR website! area = width * length\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20 = (L)(L - 8) \n" ); document.write( "20 = L^2 - 8L \n" ); document.write( "0 = L^2 - 8L - 20 \n" ); document.write( "0 = (L - 10)(L + 2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distance is positive, so the rectangle is 10 cm long and 2 cm wide. \n" ); document.write( " |