document.write( "Question 854421: Find the dimensions of the rectangle whose width is 8cm less than its length and whose area is 20 cm^2. \n" ); document.write( "
Algebra.Com's Answer #805894 by CubeyThePenguin(3113)\"\" \"About 
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area = width * length\r
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\n" ); document.write( "\n" ); document.write( "20 = (L)(L - 8)
\n" ); document.write( "20 = L^2 - 8L
\n" ); document.write( "0 = L^2 - 8L - 20
\n" ); document.write( "0 = (L - 10)(L + 2)\r
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\n" ); document.write( "\n" ); document.write( "Distance is positive, so the rectangle is 10 cm long and 2 cm wide.
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