document.write( "Question 877391: Find two consecutive positive integers such that the square of the first is decreased by 17 equals 4 times the second. \n" ); document.write( "
Algebra.Com's Answer #805875 by CubeyThePenguin(3113)![]() ![]() You can put this solution on YOUR website! consecutive positive integers: x, (x+1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 17 = 4(x+1) \n" ); document.write( "x^2 - 17 = 4x + 4 \n" ); document.write( "x^2 - 4x - 21 = 0 \n" ); document.write( "(x - 7)(x + 3) = 0 \n" ); document.write( "x = 7, x = -3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x has to be positive, so the integers are 7 and 8. \n" ); document.write( " |