document.write( "Question 877391: Find two consecutive positive integers such that the square of the first is decreased by 17 equals 4 times the second. \n" ); document.write( "
Algebra.Com's Answer #805875 by CubeyThePenguin(3113)\"\" \"About 
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consecutive positive integers: x, (x+1)\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 17 = 4(x+1)
\n" ); document.write( "x^2 - 17 = 4x + 4
\n" ); document.write( "x^2 - 4x - 21 = 0
\n" ); document.write( "(x - 7)(x + 3) = 0
\n" ); document.write( "x = 7, x = -3\r
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\n" ); document.write( "\n" ); document.write( "x has to be positive, so the integers are 7 and 8.
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