document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=921686>Question 921686</A>: <I><SPAN STYLE=\"word-break: break-all;\">  The sum of the digits of a two-digit number is 6. The number with the digits in reverse order is 6 less than twice the original number. Find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805871 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> number: AB\r<BR>\n" );
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document.write( "A + B = 6<BR>\n" );
document.write( "10B + A = 2(10A + B) - 6\r<BR>\n" );
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document.write( "Substitute B = 6 - A into the second equation.\r<BR>\n" );
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document.write( "10(6 - A) + A = 2(10A + 6 - A) - 6<BR>\n" );
document.write( "60 - 10A + A = 18A + 12 - 6<BR>\n" );
document.write( "60 - 9A = 18A + 6<BR>\n" );
document.write( "54 = 27A<BR>\n" );
document.write( "A = 2 ---> B = 4\r<BR>\n" );
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document.write( "The original number is AB = 24. </SPAN>\n" );
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