document.write( "Question 862362: Find three consecutive positive odd integers such that the product of the first and the third is less than 7 times than the second. \n" ); document.write( "
Algebra.Com's Answer #805860 by CubeyThePenguin(3113)![]() ![]() You can put this solution on YOUR website! consecutive odd integers: (x-2), x, (x+2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-2)(x+2) < 7x \n" ); document.write( "x^2 - 4 < 7x \n" ); document.write( "x^2 - 7x - 4 < 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "integer solutions: x = 0, 1, 2, 3, 4 ---> odd: 1, 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The integers have to be positive, so the integers are 1, 3, and 5. \n" ); document.write( " |