document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=917892>Question 917892</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The product of two consecutive even integers is 40 less than 8 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805797 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805797\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> consecutive even integers: x, (x+2)\r<BR>\n" );
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document.write( "x(x+2) = 8(x + (x+2)) - 40<BR>\n" );
document.write( "x^2 + 2x = 8(2x+2) - 40<BR>\n" );
document.write( "x^2 + 2x = 16x - 24<BR>\n" );
document.write( "x^2 - 14x + 24 = 0<BR>\n" );
document.write( "(x - 2)(x - 12) = 0\r<BR>\n" );
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document.write( "The integers could be 2 and 4 or 12 and 14. </SPAN>\n" );
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