document.write( "Question 899228: Find two consecutive odd integers whose product is 1 less than 6 times their sum \n" ); document.write( "
Algebra.Com's Answer #805794 by CubeyThePenguin(3113)\"\" \"About 
You can put this solution on YOUR website!
consecutive odd integers: x, (x+2)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x(x+2) = 6(x + (x+2)) - 1
\n" ); document.write( "x^2 + 2x = 6(2x+2) - 1
\n" ); document.write( "x^2 + 2x = 12x + 11
\n" ); document.write( "x^2 - 10x - 11 = 0
\n" ); document.write( "(x - 11)(x + 1) = 0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The integers are -1 and 1 or 11 and 13.
\n" ); document.write( "
\n" );