document.write( "Question 1177267: Good Day, I need help regarding this age problem.\r
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document.write( "In 6 years, Jim will be 2/3 as old as Jane: and 8 years ago, he was 1/5 years old. Find their present age.\r
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document.write( "Jim?
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document.write( "Jane? \n" );
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Algebra.Com's Answer #805773 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Assuming the statement is supposed to be that Jim 8 years ago was 1/5 AS OLD AS Jane was then.... \n" ); document.write( "Given that Jim was 1/5 as old as Jane 8 years ago, I would make the algebra easier with... \n" ); document.write( "Let x = Jim's age 8 years ago \n" ); document.write( "then 5x = Jane's age 8 years ago \n" ); document.write( "To get from 8 years ago to 6 years from now, we have to add 14 to each age: \n" ); document.write( "x+14 = Jim's age 6 years from now \n" ); document.write( "5x+14 = Jane's age 6 years from now \n" ); document.write( "Jim's age 6 years from now will be 2/3 of Jane's age then: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Their ages 8 years ago were \n" ); document.write( "Jim = x = 2 \n" ); document.write( "Jane = 5x = 10 \n" ); document.write( "Their ages now are \n" ); document.write( "ANSWERS: \n" ); document.write( "Jim = 2+8 = 10 \n" ); document.write( "Jane = 10+8 = 18 \n" ); document.write( " \n" ); document.write( " |