document.write( "Question 902781: Find three consecutive integers whose product is 208 larger that the cube of the smallest integer \n" ); document.write( "
Algebra.Com's Answer #805770 by CubeyThePenguin(3113)![]() ![]() You can put this solution on YOUR website! consecutive integers: (x-1), x, (x+1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-1)(x)(x+1) = 208 + (x-1)^3 \n" ); document.write( "x^3 - x = 208 + (x^3 - 3x^2 + 3x - 1) \n" ); document.write( "0 = -3x^2 + 4x + 207\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x is integer ---> x = 9 \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "The integers are 8, 9, and 10. \n" ); document.write( " |