document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=907584>Question 907584</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble solving this problem on my homework. There are 4 consecutive odd integers. The third is equal to the sum of the forth and twice the second. Find the 4 integers. I am completely stumped. Please help, i have a quiz tomorrow! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805760 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805760\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> consecutive odd integers: x, (x+2), (x+4), (x+6) ---> smallest of these is denoted by x\r<BR>\n" );
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document.write( "third = fourth + twice the second<BR>\n" );
document.write( "(x+4) = (x+6) + 2(x+2)<BR>\n" );
document.write( "x+4 = 3x + 10<BR>\n" );
document.write( "-6 = 2x<BR>\n" );
document.write( "x = -3\r<BR>\n" );
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document.write( "The integers are -3, -1, 1, and 3. </SPAN>\n" );
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