document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=906971>Question 906971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.when 5 is subtracted from two-thirds of a number. The result is the same when 25 is added to one-sixth of the number.find the number.<BR>\n" );
document.write( "a.58<BR>\n" );
document.write( "b.60<BR>\n" );
document.write( "c.62<BR>\n" );
document.write( "d.64<BR>\n" );
document.write( "e.66\r<BR>\n" );
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document.write( "2.1/2% + 0.86 - 2/3 is approximately _____.<BR>\n" );
document.write( "a.0.194<BR>\n" );
document.write( "b.0.196<BR>\n" );
document.write( "c.0.197<BR>\n" );
document.write( "d.0.198<BR>\n" );
document.write( "e.0.199 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805756 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805756\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. 2x/3 - 5 = x/6 + 25<BR>\n" );
document.write( "x/2 = 30<BR>\n" );
document.write( "x = 60\r<BR>\n" );
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document.write( "2. (1/2)% + 0.86 - 2/3 = 0.1983..... ---> 0.198 </SPAN>\n" );
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