document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=912400>Question 912400</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the sum of four consecutive negative integers, such that the square of the sum of the first and fourth is 289. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805714 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> consecutive integers: x, (x+1), (x+2), (x+3)\r<BR>\n" );
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document.write( "(x + (x+3))^2 = 289<BR>\n" );
document.write( "(2x+3)^2 = 289<BR>\n" );
document.write( "4x^2 + 12x + 9 = 289<BR>\n" );
document.write( "4x^2 + 12x - 280 = 0<BR>\n" );
document.write( "x^2 + 3x - 70 = 0<BR>\n" );
document.write( "(x + 10)(x - 7) = 0\r<BR>\n" );
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document.write( "The integers are negative, so x = -10 and the integers are -10, -9, -8, and -7.\r<BR>\n" );
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