document.write( "Question 919920: Find 2 consecutive positive integers such that the square of the first number is 1 more than 9 times the second number \n" ); document.write( "
Algebra.Com's Answer #805672 by CubeyThePenguin(3113)\"\" \"About 
You can put this solution on YOUR website!
consecutive positive integers: x, (x+1)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x^2 = 1 + 9(x+1)
\n" ); document.write( "x^2 = 1 + 9x + 9
\n" ); document.write( "x^2 - 9x - 10 = 0
\n" ); document.write( "(x - 10)(x + 1) = 0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The integers are positive, so x = 10 and the integers are 10 and 11.
\n" ); document.write( "
\n" );