document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=918240>Question 918240</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An integer is four less than twice another.  If the product of the two integers is 70, one pair of integers that will satisfy the problem is _________ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805670 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805670\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> integers: x, y\r<BR>\n" );
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document.write( "x = 2y - 4<BR>\n" );
document.write( "xy = 70\r<BR>\n" );
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document.write( "Substitute the first equation into the second.\r<BR>\n" );
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document.write( "(2y - 4)(y) = 70<BR>\n" );
document.write( "2y^2 - 4y = 70<BR>\n" );
document.write( "y^2 - 2y = 35<BR>\n" );
document.write( "y^2 - 2y - 35 = 0<BR>\n" );
document.write( "(y - 7)(y + 5) = 0\r<BR>\n" );
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document.write( "The integers are (x, y) = (-14, -5) and (10, 7). </SPAN>\n" );
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