document.write( "Question 921289: Positive integers x and y have a product of 56 and x < y. Seven times the reciprocal of the smaller integer plus 14 times the reciprocal of the larger integer equals 4. What is the value of x? \n" ); document.write( "
Algebra.Com's Answer #805659 by CubeyThePenguin(3113)![]() ![]() You can put this solution on YOUR website! xy = 56 \n" ); document.write( "7(1/x) + 14(1/y) = 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplify the second equation. \n" ); document.write( "7/x + 14/y = 4 \n" ); document.write( "(7y + 14x)/(xy) = 4 \n" ); document.write( "7y + 14x = 4 * 56 = 224 ----> 2x + y = 32 ---> y = 32 - 2x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute this into the first equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "xy = 56 \n" ); document.write( "x(32 - 2x) = 56 \n" ); document.write( "-2x^2 + 32x - 56 = 0 \n" ); document.write( "x^2 - 16x + 28 = 0 \n" ); document.write( "(x - 2)(x - 14) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x is the smaller integer, so x = 2 and y = 28. \n" ); document.write( " |