document.write( "Question 929355: There r 3 nos.third no is d greatest.when d 3rd no is divided by d 2nd no d quotient is 4.the
\n" ); document.write( "Diff bet d 2nd n 3rd no is654.if d 1st no is 109more than d 2nd no.find d 1st no.\r
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Algebra.Com's Answer #805642 by CubeyThePenguin(3113) $\"\"$ $\"About$

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\"There are three numbers. The third number is the greatest. When the 3rd number is divided by the 2nd number the quotient is 4. The difference between the 2nd and 3rd numbers is 654. If the 1st number is 109 more than the 2nd number, find the first number.\"\r
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\n" ); document.write( "\n" ); document.write( "1st number = x
\n" ); document.write( "2nd number = y
\n" ); document.write( "3rd number = z\r
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\n" ); document.write( "\n" ); document.write( "z/y = 4 -----> z = 4y
\n" ); document.write( "z - y = 654
\n" ); document.write( "x = y + 109\r
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\n" ); document.write( "\n" ); document.write( "Substitute the first equation into the second.\r
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\n" ); document.write( "\n" ); document.write( "4y - y = 654
\n" ); document.write( "3y = 654
\n" ); document.write( "y = 218\r
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\n" ); document.write( "\n" ); document.write( "From here, x = y + 109 = 218 + 109 = 327 \n" ); document.write( "

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