document.write( "Question 943384: find three positive consecutive odd integers such that the square of the smallest is 9 more than the sum of the other two \n" ); document.write( "
Algebra.Com's Answer #805613 by CubeyThePenguin(3113)\"\" \"About 
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consecutive odd integers: (x-2), x, (x+2)\r
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\n" ); document.write( "\n" ); document.write( "(x-2)^2 = 9 + (x + (x+2))
\n" ); document.write( "x^2 - 4x + 4 = 9 + 2x + 2
\n" ); document.write( "x^2 - 6x - 7 = 0
\n" ); document.write( "(x - 7)(x + 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "The integers could be {5, 7, 9} or {-1, 1, 3}.
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