document.write( "Question 1018748: find four consecutive odd intergers such that the sum of the second and the fourth is 17 more than one half the sum of the first and the third \n" ); document.write( "
Algebra.Com's Answer #805610 by CubeyThePenguin(3113) You can put this solution on YOUR website! 4 consecutive odd integers: x, (x+2), (x+4), (x+6)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x+2) + (x+6) = 17 + 1/2 * (x + (x+4)) \n" ); document.write( "2x + 8 = 17 + x + 2 \n" ); document.write( "x = 11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The integers are 11, 13, 15, and 17. \n" ); document.write( " |