document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=959492>Question 959492</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 9  more than 2  times another. Their product is 5  more than 3  times their sum. Find the numbers. Answer in the form of paired points with the lowest of the two integers first </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805597 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805597\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = larger number<BR>\n" );
document.write( "y = smaller number\r<BR>\n" );
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document.write( "x = 2y + 9<BR>\n" );
document.write( "xy = 3(x + y) + 5\r<BR>\n" );
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document.write( "Substitute x into the second equation.\r<BR>\n" );
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document.write( "(2y + 9)(y) = 3(2y + 9 + y) + 5<BR>\n" );
document.write( "2y^2 + 9y = 3(3y + 9) + 5<BR>\n" );
document.write( "2y^2 + 9y = 9y + 32<BR>\n" );
document.write( "2y^2 = 32<BR>\n" );
document.write( "y^2 = 16<BR>\n" );
document.write( "y = 4 or -4\r<BR>\n" );
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document.write( "The integers are (x, y) = (17, 4) or (1, -4) </SPAN>\n" );
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