document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=952323>Question 952323</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of 2 integers is 25. One less than twice the larger integer is equal to one more than four times the smaller integer. Find the integers <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805589 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = larger integer<BR>\n" );
document.write( "y = smaller integer\r<BR>\n" );
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document.write( "x + y = 25<BR>\n" );
document.write( "2x - 1 = 4y + 1\r<BR>\n" );
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document.write( "Rearranging the first equation, we get x = 25 - y. We can substitute this into the second equation.\r<BR>\n" );
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document.write( "2x - 1 = 4y + 1<BR>\n" );
document.write( "2(25 - y) - 1 = 4y + 1<BR>\n" );
document.write( "50 - 2y - 1 = 4y + 1<BR>\n" );
document.write( "48 = 6y<BR>\n" );
document.write( "8 = y\r<BR>\n" );
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document.write( "The integers are 17 and 8. </SPAN>\n" );
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