document.write( "Question 1022609: find three consecutive positive integers such that the product of the larger two is equal to twice the second integer plus twice the sum of all three integers \n" ); document.write( "

Algebra.Com's Answer #805586 by CubeyThePenguin(3113) $\"\"$ $\"About$

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consecutive positive integers: (x-1), x, (x+1)\r
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\n" ); document.write( "\n" ); document.write( "x(x+1) = 2x + 2((x-1) + x + (x+1))
\n" ); document.write( "x^2 + x = 2x + 6x
\n" ); document.write( "x^2 - 7x = 0
\n" ); document.write( "x(x-7) = 0
\n" ); document.write( "x = 0, 7\r
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\n" ); document.write( "\n" ); document.write( "The integers are positive, so the integers are 6, 7, and 8. \n" ); document.write( "

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