document.write( "Question 954855: find two consecutive integers such that the square of the sum of the two integers is 8 more than the first integer. \n" ); document.write( "
Algebra.Com's Answer #805578 by CubeyThePenguin(3113) You can put this solution on YOUR website! consecutive integers: x, (x+1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x + (x+1))^2 = x + 8 \n" ); document.write( "(2x+1)^2 = x + 8 \n" ); document.write( "4x^2 + 4x + 1 = x + 8 \n" ); document.write( "4x^2 + 3x - 7 = 0 \n" ); document.write( "(x - 1)(4x + 7) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The integers are 1 and 2. \n" ); document.write( " |