document.write( "Question 1177200: A ball is thrown vertically downward from the top of a building, leaving the thrower’s hand with a velocity
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document.write( "of 30 ft/s.
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document.write( "(a) What will be its velocity after falling for 2 sec? \n" );
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Algebra.Com's Answer #805563 by Solver92311(821)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your units are feet and seconds, so distance in feet, time in seconds, the magnitude of velocity is feet per second, and magnitude of the acceleration is feet per second per second.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The presumption here is that the building in the story is on the surface of planet Earth where the acceleration due to gravity is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The height as a function of time for an object traveling vertically with respect to the earth's surface is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Where \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The instantaneous velocity as a function of time for this situation is the first derivative of the height function, namely:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can do your own arithmetic.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( "\n" ); document.write( "From \n" ); document.write( "I > Ø \n" ); document.write( " |