document.write( "Question 974869: What is the smallest possible integer that's greater than 100, and leaves a remainder of 1, when divided by 3; a remainder of 2, when divided by 5; and a remainder of 3, when divided by 7? \n" ); document.write( "
Algebra.Com's Answer #805533 by CubeyThePenguin(3113)![]() ![]() You can put this solution on YOUR website! x = 1 mod 3 \n" ); document.write( "x = 2 mod 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First find the integers that satisfy the first two conditions. The first number that works is 7, the next is 22, and so on. Any number of the form 7 + 15n, where n is a positive integer, leaves a remainder of 1 when divided by 3 and a remainder of 2 when divided by 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7 + 15n > 100 \n" ); document.write( "15n > 93 \n" ); document.write( "n > 6.2 ----> n = 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We will start looking from 7 + 15(7) = 112 and beyond. 112 is divisible by 7 and 15 leaves a remainder of 1 when divided by 7, so the number that satisfies all three conditions is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "112 + 15(3) = 157. \n" ); document.write( " |