document.write( "Question 969156: An integer is three more than another integer. Twice the larger integer is two less than the square of the smaller integer. Find the two integers \n" ); document.write( "
Algebra.Com's Answer #805529 by CubeyThePenguin(3113)\"\" \"About 
You can put this solution on YOUR website!
larger integer = x
\n" ); document.write( "smaller integer = y\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = y + 3
\n" ); document.write( "2x = y^2 - 2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Use substitution.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2(y + 3) = y^2 - 2
\n" ); document.write( "2y + 6 = y^2 - 2
\n" ); document.write( "0 = y^2 - 2y - 8
\n" ); document.write( "0 = (y - 4)(y + 2)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The integers are (x, y) = (7, 3) or (1, -2).
\n" ); document.write( "
\n" );