document.write( "Question 110548: solve the system by substitution.\r
\n" ); document.write( "\n" ); document.write( "x + y = 12\r
\n" ); document.write( "\n" ); document.write( "y = 2x
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Algebra.Com's Answer #80552 by HyperBrain(694)\"\" \"About 
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\"x+%2B+y+=+12\"\r
\n" ); document.write( "\n" ); document.write( "But, \"y=2x\". So,\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B%282x%29=12\"
\n" ); document.write( "\"x%2B2x=12\"
\n" ); document.write( "\"3x=12\"
\n" ); document.write( "\"3x%2F3=12%2F3\"
\n" ); document.write( "\"x%283%2F3%29=4\"
\n" ); document.write( "\"x%2A1=4\"
\n" ); document.write( "\"x=4\"\r
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\n" ); document.write( "\n" ); document.write( "Again, \"y=2x\" So,\r
\n" ); document.write( "\n" ); document.write( "\"y=2%2A4=8\"\r
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\n" ); document.write( "\n" ); document.write( "Thus, x=4 and y=8.\r
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\n" ); document.write( "\n" ); document.write( "Power up,
\n" ); document.write( "HyperBrain!
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