document.write( "Question 1177230: 1-The length of time a domestic flight must wait between gate departure and takeoff taxi at Miami International Airport is approximately normally distributed with a mean of 20 minutes and a standard deviation of 5 minutes.
\n" ); document.write( "a. What is the probability that a plane must wait between 18 and 24 minutes before taxiing for takeoff after leaving the gate?
\n" ); document.write( "b. What is the probability a plane must wait between 22 and 30 minutes before taxiing for takeoff after leaving the gate?
\n" ); document.write( "c. What is the probability a plane waits more than 12 minutes between gate departure and takeoff taxi?
\n" ); document.write( "d. What is the length of time such that only 5% of planes wait this long or longer before gate departure and taxiing down the runway? \n" ); document.write( "
Algebra.Com's Answer #805518 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Hi\r\n" );
document.write( "NOrmal Distribution:     μ = 20min    σ = 5min \r\n" );
document.write( "Using TI or similarly an inexpensive calculator like a Casio fx-115 ES plus\r\n" );
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document.write( "a P( 18 < x < 24) = normalcdf(18,24, 20, 5) = .4436\r\n" );
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document.write( "b. P( 22 < x < 30)= normalcdf(22,30, 20, 5) = .3218\r\n" );
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document.write( "c. P( x > 12) = 1 - P(x ≤  12) - 1 - normalcdf(-9999, 12, 20,5) = 1-.0548 = .9452\r\n" );
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document.write( "d. z = invNorm(.05)  = 1.645= (x-20)/5   ⇒  x = 28.225min\r\n" );
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document.write( "Wish You the Best in your Studies.\r\n" );
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