document.write( "Question 1177203: The orbits of Earth and Venus around the Sun are almost circular, and in the same plane.
\n" ); document.write( "Earth is 1.496* 10^8 km from the Sun.
\n" ); document.write( "Venus is 1.082* 10^8 km from the Sun.
\n" ); document.write( "Treating the space between the orbits as an annulus, calculate its area.
\n" ); document.write( "Write your answer in scientific notation correct to 2 significant figures.
\n" ); document.write( "

Algebra.Com's Answer #805510 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
assuming their orbits are circular, then you would use the area of a circle formula, which is:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "A = pi * r ^2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "pi represents the constant value of 3.142592654.....\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the radius of the path of earth around the sun is equal to 1.496 * 10^8 kilometers.
\n" ); document.write( "the radius of the path of venus around the sun is equal to 1.082 * 10^8 kilometers.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the sun is assumed to be the center of the circle that these two planets revolve around.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "to find the area of the annulus, find the area of the circle made by the earth and subtract the area made by venus around the sun.
\n" ); document.write( "what's left is the area between the earth and venus.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "that's the annulus.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the area of the larger circle is equal to pi * (1.496 * 10^8)^2 = 7.030934624 * 10^16.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the area of the smaller circle is equal to pi * (1.082 * 10^8)^2 = 3.677937918 * 10^26.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the area of the annulus is the larger area minus the smaller area = 3.352996706 * 10^16.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "here's a reference.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "https://www.mathsisfun.com/geometry/annulus.html\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );