document.write( "Question 1177203: The orbits of Earth and Venus around the Sun are almost circular, and in the same plane.
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document.write( "Earth is 1.496* 10^8 km from the Sun.
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document.write( "Venus is 1.082* 10^8 km from the Sun.
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document.write( "Treating the space between the orbits as an annulus, calculate its area.
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document.write( "Write your answer in scientific notation correct to 2 significant figures. \n" );
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Algebra.Com's Answer #805510 by Theo(13342)![]() ![]() You can put this solution on YOUR website! assuming their orbits are circular, then you would use the area of a circle formula, which is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = pi * r ^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "pi represents the constant value of 3.142592654.....\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the radius of the path of earth around the sun is equal to 1.496 * 10^8 kilometers. \n" ); document.write( "the radius of the path of venus around the sun is equal to 1.082 * 10^8 kilometers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the sun is assumed to be the center of the circle that these two planets revolve around.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to find the area of the annulus, find the area of the circle made by the earth and subtract the area made by venus around the sun. \n" ); document.write( "what's left is the area between the earth and venus.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's the annulus.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the area of the larger circle is equal to pi * (1.496 * 10^8)^2 = 7.030934624 * 10^16.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the area of the smaller circle is equal to pi * (1.082 * 10^8)^2 = 3.677937918 * 10^26.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the area of the annulus is the larger area minus the smaller area = 3.352996706 * 10^16.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a reference.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "https://www.mathsisfun.com/geometry/annulus.html\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |