document.write( "Question 1177182: $39,900 is invested for 6 months at 8% p.a.
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Algebra.Com's Answer #805456 by MathLover1(20850)\"\" \"About 
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\"A+=+P%281+%2B+rt%29\"\r
\n" ); document.write( "\n" ); document.write( "First, converting \"R\" percent to \"r\" a decimal
\n" ); document.write( "\"r+=+R%2F100+=+8%2F100+=+0.08\" per year.\r
\n" ); document.write( "\n" ); document.write( "Putting time into years for simplicity,
\n" ); document.write( "\"6%2F12\" year = \"0.5\" years \r
\n" ); document.write( "\n" ); document.write( "Solving our equation:\r
\n" ); document.write( "\n" ); document.write( "\"A+=+39000%281+%2B+%280.08+%2A+0.5%29%29+\"
\n" ); document.write( "\"A+=+40560.00\"=>the future value \r
\n" ); document.write( "\n" ); document.write( "The total amount accrued, principal plus interest, from simple interest on a principal of $\"39000.00\" at a rate of \"8\"% per year for \"0.5\" years (\"6\" months) is $\"40560.00\".\r
\n" ); document.write( "\n" ); document.write( "\"I+=+A+-+P+=40560.00-39000+=1560.00\"=> interest earned\r
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