document.write( "Question 1001805: Jenna's pockets were heavy with coins. She had three times as many dimes as quarters, and 2 less nickels than dimes. If she had a total of $6.20, how many of each type of coin did she have? \n" ); document.write( "
Algebra.Com's Answer #805397 by CubeyThePenguin(3113)\"\" \"About 
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n = number of nickels
\n" ); document.write( "d = number of dimes
\n" ); document.write( "q = number of quarters\r
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\n" ); document.write( "\n" ); document.write( "q = 3d
\n" ); document.write( "n = d - 2
\n" ); document.write( "5n + 10d + 25q = 620\r
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\n" ); document.write( "\n" ); document.write( "Write everything in terms of d.\r
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\n" ); document.write( "\n" ); document.write( "5(d - 2) + 10d + 25(3d) = 620
\n" ); document.write( "5d - 10 + 10d + 75d = 620
\n" ); document.write( "90d = 630
\n" ); document.write( "d = 7\r
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\n" ); document.write( "\n" ); document.write( "There were 5 nickels, 7 dimes, and 21 quarters.
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