document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1006993>Question 1006993</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A restaurant bill of $2.85 was paid using quarters and dimes only. If twice the number of quarters is 6 less than 4 times the number of dimes, how many quarters were used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #805347 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=805347\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d = number of dimes<BR>\n" );
document.write( "q = number of quarters\r<BR>\n" );
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document.write( "10d + 25q = 285<BR>\n" );
document.write( "2q = 4d - 6\r<BR>\n" );
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document.write( "Substitute q = 2d - 3 into the first equation.\r<BR>\n" );
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document.write( "10d + 25(2d - 3) = 285<BR>\n" );
document.write( "10d + 50d - 75 = 285<BR>\n" );
document.write( "60d = 360<BR>\n" );
document.write( "d = 6\r<BR>\n" );
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document.write( "6 dimes were used and 9 quarters were used. </SPAN>\n" );
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