document.write( "Question 1177107: consider the sequence of numbers: 2;5;2;9;2;13;2;17\r
\n" ); document.write( "\n" ); document.write( "calculate the sum of the first 100 terms of the sequence
\n" ); document.write( "

Algebra.Com's Answer #805341 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"2\",\"5\",\"2\",\"9\",\"2\",\"13\",\"2\",\"17\",...\r
\n" ); document.write( "\n" ); document.write( "pattern:\r
\n" ); document.write( "\n" ); document.write( "all odd number terms are equal, \"2\"
\n" ); document.write( "in \"100\" terms you have \"50\" of them; so their sum is \"50%2A2=100\"\r
\n" ); document.write( "\n" ); document.write( "all even number terms, you also have \"50\" of them, have common difference \"4\";\r
\n" ); document.write( "\n" ); document.write( "\"5\"
\n" ); document.write( "\"5%2B4=9\"
\n" ); document.write( "\"9%2B4=13\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "and so on, and the formula for nth term of an arithmetic progression is \r
\n" ); document.write( "\n" ); document.write( " \"a%5Bn%5D=a%5B1%5D%2Bd%28n-1%29\" where \"a%5B1%5D=5\" and \"d=4\"
\n" ); document.write( "\"a%5Bn%5D=5%2B4%28n-1%29\"
\n" ); document.write( "\"a%5Bn%5D=5%2B4n-4\"
\n" ); document.write( " so.\"a%5Bn%5D=4n%2B1\" \r
\n" ); document.write( "\n" ); document.write( "sum of all even number terms is:\r
\n" ); document.write( "\n" ); document.write( "\"S%5Bn%5D=%28n%2F2%29%282a%5B1%5D%2B4%28n-1%29+%29\"
\n" ); document.write( "\"S%5B50%5D=%2850%2F2%29%282%2A5%2B4%2850-1%29+%29\"
\n" ); document.write( "\"S%5B50%5D=5150\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "add both odd and even terms sums \r
\n" ); document.write( "\n" ); document.write( "\"S%5B100%5D=100%2B5150\"\r
\n" ); document.write( "\n" ); document.write( "\"S%5B100%5D=5250\"->the sum of the first \"100\" terms \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );