document.write( "Question 1177016: EVOL is a cyclic quadrilateral, inscribed in a circle with center S. Given that the radius of this circle is 25 in. and angle VEL is 55 degrees. explain your work to find the following measurements.
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Algebra.Com's Answer #805338 by mccravyedwin(407)\"\" \"About 
You can put this solution on YOUR website!

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document.write( "Let the center be K. Draw radii KV and KL [which are 25 in. each. We'll get\r\n" );
document.write( "that in part d)].  Let's answer part b) first\r\n" );
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b)Angle measure of Minor Arc VL
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document.write( "Since inscribed angle VEL is 55°, then 55° is one-half the measure of\r\n" );
document.write( "its intercepted arc.  So minor arc VL is twice 55°, or 110°.\r\n" );
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document.write( "Let's do part a) next\r\n" );
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a)Length of Major Arc VL
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document.write( "The measure of major arc VL = 360°-the measure of minor arc VL \r\n" );
document.write( "= 360-°110°=250° \r\n" );
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document.write( "Let's do part c) next\r\n" );
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c)Angle VOL
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document.write( "Since inscribed angle VOL subtends major acc VL, which is 250°, then 250° is\r\n" );
document.write( "one-half the measure of its intercepted arc. So angle VOL is 125°  \r\n" );
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d)Length of Chord VL
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document.write( "Since we found minor arc VL to have measure 110° in part a), Central angle\r\n" );
document.write( "VKL also has measure 110°.\r\n" );
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document.write( "Now we will draw KP perpendicular to VL.  \r\n" );
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d)Length of Chord VL
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document.write( "Since triangle VKL is isosceles, KP bisects angle VKL, which is 110°, and\r\n" );
document.write( "angle VKP is 55°.\r\n" );
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document.write( "\"sin%28VKP%29=opposite%2Fhypotenuse=VP%2FVK\"\r\n" );
document.write( "\"sin%2855%5Eo%29=VP%2F25\"\r\n" );
document.write( "\"25sin%2855%5Eo%29=VP\"\r\n" );
document.write( "\"20.47880111=VP\"\r\n" );
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document.write( "Since chord VL is twice VP, chord VL has length 40.95760221,\r\n" );
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document.write( "Edwin
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