document.write( "Question 1177096: Hi
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document.write( "A B C D had some stickers.5/11 of the total belonged to B. The ratio of the number of stickers A had to the total number owned by B C D was 1;7 respectively. C had 1/3 as many as what A B and D had in total. If C had 72 fewer than B how many did they have altogether.
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document.write( "Thank you \n" );
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Algebra.Com's Answer #805335 by greenestamps(13215) You can put this solution on YOUR website! \n" ); document.write( "B has 5/11 of the stickers; that is given directly. \n" ); document.write( "\"The ratio of the number of stickers A had to the total number owned by B C D was 1:7.\" That means A has 1/8 of the stickers. \n" ); document.write( "\"C had 1/3 as many as what A B and D had in total.\" That means C had 1/4 of the stickers. \n" ); document.write( "C had 72 fewer stickers than B: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: Together they had 352 stickers. \n" ); document.write( " \n" ); document.write( " |